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takolin
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Post subject: Re: To Smart people (and to future Chemists & Mathematicians) Posted: Tue Apr 15, 2008 1:39 pm |
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Senior Member |
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Joined: Jan 2007 Posts: 4238 Location: Life
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don't know if the pH problem is solved, but I cba checking pages and he should've updated the questions.
pH = -log[H+] 1.2 = -log[H+] -1.2 = log [H+] 10^(-1.2) = 0.063
Thus the concentration of the strong acid is 0.063M.
Mass problem.
50% NaOH => 500g NaOH in a 1L solution. But you don't know the density of the solution, thus you don't know the weight of the solution. Density of pure water isn't the same as the density of a solution. Thus afaik, you can't solve the problem due to lack of information.
Let's say the density is 1kg/l (not true, but it's an assumption)
Thus you'd have 500g/40g/mol = 12.5M.
Are you sure that the answer is 19M? If yes
19M*40 = 760g of NaOH. Density would be 1520g/l (missing value you need).
I <3 chem.
[edit]I googled the density and it's 1.53kg/l
Thus 1 litre = 1530 grams. => 765g of NaOH. => 765g/40g/mol = 19.125M
19.125M solution
[/edit]
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