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I have this big assed test JUST on balancing chemical equations, and i need HALP!

We got this revview with a bunch of balancing questions and im looking at the bigger ones with like 5-6 elements with a few polyatomic ions in it thinking "....wtf"

My friend and I were attempting to do the bigger questions since they were harder and we came across a friggan equation like this:

__(NH4)3PO4 + __Pb(NO3)4 -> __Pb3(PO4)4 + __NH4NO3

We spent nearly the whole class trying to answer that question (We were using the table chart way because thats the only way we've learnt so far)

Can anybody give me tips or tricks to do balancing equations faster? Done

I have a chemistry unit test tomorrow and im cramming atm.

Before i ask this question..I WAS NEVER GOOD AT SCIENCE.

Kay..so im doing review questions and theres this question that says



The answer i came up with is

Element Q= Nitrogen (Cation)
Element X= Beryllium (Anion)

But this makes no sense, i've never heard of a compound made of nitrogen+beryllium...HALP.

4...3... --> 1...12...

just keep trying, nothin to it

How did you get that so fast? Did you just keep doing guess and check?

Ugh I used to know how to do this.

yea, just keep trying to balance them out. it's all trial and error.

im good at chemical


(±)-1-(benzo[d][1,3]dioxol-5-yl)-N-methylpropan-2-amine = fun

Wth does that mean?

Teach meeeeeeee

no idea...


but its soooooooooooo gooooooooooooooooooooood

__(NH4)3PO4 + __Pb(NO3)4 -> __Pb3(PO4)4 + __NH4NO3

From what i learned in chemistry class, when balancing equations:

Balance the metals first (in this case, Pb)
Next, balance polyatomic ions (NH4,PO4,NO3) make any adjustments to metals if necessary
Then balance non-metals (none in this case), make adjustments
And finally, hydrogen and oxygen (also none), make adjustments

So, following these rules, the first step looks like this:
__(NH4)3PO4 + 3Pb(NO3)4 -> __Pb3(PO4)4 + __NH4NO3

Then you go for the polyatomic ions

__(NH4)3PO4 + 3Pb(NO3)4 -> __Pb3(PO4)4 + 12NH4NO3

4(NH4)3PO4 + 3Pb(NO3)4 -> __Pb3(PO4)4 + 12NH4NO3

and finally, fill in the last blank with a one, since the equation is balanced

4(NH4)3PO4 + 3Pb(NO3)4 -> 1Pb3(PO4)4 + 12NH4NO3


http://en.wikipedia.org/wiki/Vernallagra wtf O_o

chemical equations. I love them.They are so easy

mdma

guess what this is

[1R-(exo,exo)]-3-(Benzoyloxy)-8-methyl-8-azabicyclo [3.2.1] Octane-2-Carboxylic Acid Methylesters 3-beta-hydroxy-1-alpha-H, 5-alpha-H tropane-2-beta-carboxylic-acid methyl ester benzoate


or

[1R-(exo,exo)] -3-(benzoyloxy)-8-methyl-8-azabicyclo[3.2.1]octane-2-carboxylic acid methyl ester

and this is real, pretty sure everyone know what it is on this forum or even used it...

Isn't that vinegar? :S

umm no vinegar is HC2H3O2, acetic acid, or simply ethanoic acid

i know this cuz i am crazy good luck gussing what that thing is ^

If in doubt. Say cocaine.

1R-(exo,exo)] -3-(benzoyloxy)-8-methyl-8-azabicyclo[3.2.1]octane-2-carboxylic acid methyl ester

Chaos could you give me an example where you would have to make adjustments?

?!!!!!!!!!! was that a complete random guess or did u search frantically on google?

I guessed it was cocain after reading it a few times then reading SMS' post lul

The example I'm giving you isn't the best one. I'll go dig up my notes, and if I happen to find a better one, I'll post it then.

Consider CaCl2 + AgNO3 --> AgCl + Ca(NO3)2
first balance the metals Ca and Ag:
1CaCl2 + AgNO3 --> 1AgCl + 1Ca(NO3)2

Next, we move onto polyatomic ion NO3:
1CaCl2 + 2AgNO3 --> 1AgCl + 1Ca(NO3)2

Since we've added a two in front of AgNO3, we have to go back and change the balancing of Ag:
1CaCl2 + 2AgNO3 --> 2AgCl + 1Ca(NO3)2

the non-metal, Cl, is already balanced.
there are no hydrogen or oxygen.

so therefore, 1CaCl2 + 2AgNO3 --> 2AgCl + 1Ca(NO3)2

In the second step, where we balance out the polyatomic ion NO3, we made an adjustment to Ag, which was step one. So, we had to go back and readjust Ag.

try to balance something with this

http://en.wikipedia.org/wiki/Acetylsery ... o...serine

BAHAHAHAHAHAHAHHAHAHAAHAHA

Oxidation/reduction balancing is the most difficult thing to do if you need to balance.
(It's still easy as hell)

Your solution was a simple one.

You could even try doing it like this.


3x + y + z + 4t = 3z + 4y + x + t

Now it's math instead of chem.
Just find the solution for this equation with the lowest possible whole number (it should have a name, but I forgot), because there are infinity solutions.

its not that balancing thats the problem its the rest of the stoichiometry thats a pain in the arse.

Isn't that Physics?

its a large part of chemistry...

Basically the 3 big sciences go like this

Physics->Chemistry->Biology

Physics doesn't incorporate Biology and is the bases of the laws needs for Chemistry.
Chemistry requires knowledge of physics and is the basis of laws for Biology.
Biology doesn't need physics but requires knowledge of Chemistry.

Physics = Nucleus
Chemistry = Electrons
Bio = Who cares

In a nut shell, of course there are exceptions

used to be good @ this, dropped my chemistry class tho

how about this...

3,7-Dihydro-3,7-dimethyl-1H-purine-2,6-dione; 3,7-Dimethylxanthine

everyone loves it

is that chawklit?

I usually just make a chart of the # of chemicals left and right if its gets too confusing... that was way back in high school. So glad I am done with organic chemistry, hard as hell

Yea, I learned this last year (Sophmore) from a Dr. and I understood it then but since he was the 2nd worst teacher I ever had I forgot it all.