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nitrofreez
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Post subject: Chemistry problem help  Posted: Sat Sep 20, 2008 7:23 pm |
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So I've gotten some homework for chemistry, and the last question is:
How many molecules (not moles) of NH3 are produced from 6.42×10^−4 g of H2?
Chemical formula: 3H2 (g) + N2 (g)---> 2NH3 (g)
I've been trying this problem for a while but I still can't get it. So,my question is, how would I go about solving this problem? Any help is much appreciated.
-Nitro
EDIT: It's 6.42×10^−4 not 10-4, sorry. Thanks crazy.
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BF3 ID: Alpinewolf007
Though I Fly Through the Valley of Death, I Shall Fear No Evil. For I am at 80,000 Feet and Climbing.
Last edited by nitrofreez on Sat Sep 20, 2008 7:53 pm, edited 1 time in total.
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crazyskwrls
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Post subject: Re: Chemistry problem help Posted: Sat Sep 20, 2008 7:43 pm |
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ThiefzV2 wrote: 5.56x10^20 i beg to differ, 1.28*10^20 6.42×10−4 g i guess this is supposed to be 6.42×10 ^−4 g
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thnx Kraq
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ThiefzV2
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Post subject: Re: Chemistry problem help Posted: Sat Sep 20, 2008 7:57 pm |
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Quote: 6.42×10−4 g
i guess this is supposed to be 6.42×10^−4 g yes thats what he meant crazyskwrls wrote: ThiefzV2 wrote: 5.56x10^20 i beg to differ, 1.28*10^20 No
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nitrofreez
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Post subject: Re: Chemistry problem help Posted: Sat Sep 20, 2008 7:57 pm |
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Incidentally, would you be able to explain to me how you got the answer Crazy? You were right but I'd like to know how you did it for future reference
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BF3 ID: Alpinewolf007
Though I Fly Through the Valley of Death, I Shall Fear No Evil. For I am at 80,000 Feet and Climbing.
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crazyskwrls
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Post subject: Re: Chemistry problem help Posted: Sat Sep 20, 2008 8:09 pm |
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ThiefzV2 wrote: Quote: 6.42×10−4 g
i guess this is supposed to be 6.42×10^−4 g yes thats what he meant crazyskwrls wrote: ThiefzV2 wrote: 5.56x10^20 i beg to differ, 1.28*10^20 No pwned  6.42×10^−4 g H2 has molar mass of 2 6.42×10^−4 g/2 = 3.21×10^−4 mol of H2since according to the equation for every 3 mol of H2, 2 mol of NH3 is produced so 3.21×10^−4 mol of H2 * (2/3) = 2.14*10^-4 mol of NH3avogadro's number is 6.02*10^23 2.14*10^-4 mol of NH3 * 6.02*10^23 = 1.28*10^20
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thnx Kraq
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SM-Count
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Post subject: Re: Chemistry problem help Posted: Sat Sep 20, 2008 8:17 pm |
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Crazy has the correct answer but the wrong explanation. You never use H2 to calculate molar mass, you use H with 1g, but the conversion ration 6 moles of hydrogen to 2 moles of ammonia.
Last edited by SM-Count on Sat Sep 20, 2008 8:18 pm, edited 1 time in total.
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Ashikiheyun
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Post subject: Re: Chemistry problem help Posted: Sun Sep 21, 2008 4:42 am |
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Lord how I do NOT miss chemistry at all. 
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Playing on Devias SRO - Ashikiheyun if you want a guild PM me here or in-game.
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