Silkroad Online Forums

- if u are a lvl 19 blade using lvl 19 KD skill, how many hit average needed to KD a lvl 90
- what's the formula to calculate the probability of KD?

Each shot has 50% for Lv19, so take 19 away from 90 and divide the percentage. Clearly that's wrong - and I've got no idea what I'm talking about, rather a stab in the dark. but hey!

(IF my calculation was correct it would take 21 shots? but you probably have greater chance than that)

You cant determinate the number of shots needed, it could be 1st try or 10th

You have a % of chance each shot i think.

Like if a lvl 19 tries to kb a lvl 90, he has a litle % of chance to kd him each shot

Shh Kratos, I put 3 seconds into my formula.

Well even two 90's kding one another over and over again don't always get the kd. So the chance could be like 1% chance for a 19 to kd a 90, but still kd on the first try. xP

-.- when im pvping (im lvl 90) i get KD by lvl 19-30 players... All the time!

I know, but im asking about the average hit needed.

it's a mystery

what you need to calculate is how does the % decrease when you you fight a player lvl 20,21,22,23,24...etc till 90

like 50% vs a lvl 19, 49% vs a lvl 20...and so on?

xD

It's weird.

I have lv 1 Demon Blade force and lv 1 soul blade force at level 78. As far as my experience can tell, roughly 1/3 of lv 63 KD's can knock down the mages, and 1/7 of level 43 KD's.

i will try but i dont think iam right
lvl 19 = 50% chance
lvl 38 = 25% chance
lvl 76 = 12.5% chance
i dunno the rest

If it's so, i can guess the formula would be:

probability of KD = 50% - (enemy lvl - skill lvl)%

lv 63 KD has 35% KD on lvl 78 ie 35*3=105>100
lv 43 KD has 15% KD on lvl 78 ie 15*7=105>100

Makes plenty of sense, but it doesn't work for large numbers, e.g. lv 90 knocked down by level 19 skill.