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ThatBluePerson
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Post subject: could it be? OMG math Posted: Wed Apr 29, 2009 9:04 pm |
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Joined: Jun 2007 Posts: 1647 Location: Earth
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So today we had the state test that we have to take thanks to NCLB, for my sophomore class. It was Math. I practically finished all 62 questions in about an hour and a half. Except one question:  If I replicated it correctly from memory. Anyways, I spent like the whole day trying to figure out the answer and I just couldn't. I know I will feel like a douche when you guys tell me right answer. But I just kept on trying and trying with everything I could think of and nothing. So now my perfect score streak since 1st grade is broken. After some cursing out loud and getting escorted to the gym to finish there, I gave up and randomly selected B.
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boast
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Post subject: Re: could it be? OMG math Posted: Wed Apr 29, 2009 9:17 pm |
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Joined: Jan 2007 Posts: 477 Location:
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was there an E. None of the above
_________________ BlessedSoul - Battle Bard • Wartune - Warrior
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evilpeta
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Post subject: Re: could it be? OMG math Posted: Wed Apr 29, 2009 9:17 pm |
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you sure the correct answer is within those options? lol idk if im right cuz this is old stuff but the volume of a cilinder is the area of the circunference times the height. area of circunference = pi*radius^2, and height = h. so: r = x/2, h = 6x V = pi*(radius)^2*height V = pi*(x/2)^2*6x V = pi*(x^2/4)*6x V = (3/2)*pi*x^3
so the answer is E) none of the above. or F) this test sucks balls.
_________________ wat
Last edited by evilpeta on Wed Apr 29, 2009 9:21 pm, edited 2 times in total.
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Reise
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Post subject: Re: could it be? OMG math Posted: Wed Apr 29, 2009 9:18 pm |
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Joined: May 2006 Posts: 6650 Location:
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I suck at this stuff but I know the answer isn't A or B.
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ThatBluePerson
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Post subject: Re: could it be? OMG math Posted: Wed Apr 29, 2009 9:24 pm |
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Joined: Jun 2007 Posts: 1647 Location: Earth
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Yeah my algebrator says that the answer is 3PIx^3 which is what I got when I first worked out the problem.
damn TAKS creators.... no there was no E.
Last edited by ThatBluePerson on Wed Apr 29, 2009 9:25 pm, edited 1 time in total.
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_Angels
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Post subject: Re: could it be? OMG math Posted: Wed Apr 29, 2009 9:24 pm |
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Joined: Nov 2007 Posts: 707 Location:
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evilpeta wrote: you sure the correct answer is within those options? lol idk if im right cuz this is old stuff but the volume of a cilinder is the area of the circunference times the height. area of circunference = pi*radius^2, and height = h. so: r = x/2, h = 6x V = pi*(radius)^2*height V = pi*(x/2)^2*6x V = pi*(x^2/4)*6x V = (3/2)*pi*x^3
so the answer is E) none of the above. or F) this test sucks balls. You are my new hero...
_________________ << banned on request. -cin >>
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ThatBluePerson
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Post subject: Re: could it be? OMG math Posted: Wed Apr 29, 2009 9:30 pm |
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_Angels wrote: evilpeta wrote: you sure the correct answer is within those options? lol idk if im right cuz this is old stuff but the volume of a cilinder is the area of the circunference times the height. area of circunference = pi*radius^2, and height = h. so: r = x/2, h = 6x V = pi*(radius)^2*height V = pi*(x/2)^2*6x V = pi*(x^2/4)*6x V = (3/2)*pi*x^3
so the answer is E) none of the above. or F) this test sucks balls. You are my new hero...but isn't 6*1/2=3? or i'm i a math noob?
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evilpeta
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Post subject: Re: could it be? OMG math Posted: Wed Apr 29, 2009 9:36 pm |
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you don't get to multiply 6 times 1/2 since the 1/2 turns into 1/4 due to radius squared. lets take X out of the equation so it's easier to see. radius = 1/2, height = 6 Volume = pi * (radius)^2 * height V = pi * (1/2)^2 * 6 V = pi * 1/4 * 6 V = pi * 3/2
now you can just assume it's x^3 since its a volume, volume is measured in units ^3 meters^3, etc etc.
_________________ wat
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EvGa
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Post subject: Re: could it be? OMG math Posted: Wed Apr 29, 2009 9:43 pm |
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Joined: Apr 2008 Posts: 2612 Location: Texas
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Like evilpeta said, answer is: (3/2)pi(x^3).
pi*r^2*h Pi*((1/2)x)^2)*(6x) =Pi*(1/4)*(x^2)*(6x) =Pi*(3/2)*(x^3) =(3/2)*pi*(x^3)
Answer isn't there.
EDIT: Doh evil replied again.. easier to understand the way he put it.
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Last edited by EvGa on Wed Apr 29, 2009 9:56 pm, edited 3 times in total.
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ThatBluePerson
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Post subject: Re: could it be? OMG math Posted: Wed Apr 29, 2009 9:44 pm |
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Joined: Jun 2007 Posts: 1647 Location: Earth
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 still.. now that im thinking that 2/3 could of been a 3/2
Last edited by ThatBluePerson on Wed Apr 29, 2009 9:46 pm, edited 1 time in total.
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EvGa
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Post subject: Re: could it be? OMG math Posted: Wed Apr 29, 2009 9:45 pm |
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You're messing up at the very beginning. Radius = (1/2)x. You have to square the radius, thus you have to square 1/2 AND x. (1/2) squared = (1/4).
So ((1/2)x)^2 = (1/4)x^2
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evilpeta
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Post subject: Re: could it be? OMG math Posted: Wed Apr 29, 2009 9:46 pm |
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that is a common mistake, you're just squaring the X, and not the 1/2 before it.  ps: evga, typo on your first post. 
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ThatBluePerson
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Post subject: Re: could it be? OMG math Posted: Wed Apr 29, 2009 9:47 pm |
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evilpeta wrote: that is a common mistake, you're just squaring the X, and not the 1/2 before it.  my teacher use to yell at us for that, i learned if (1/2x)^2 then we square both but if 1/2x^2 then the x is only square. but probably since the ^2 is part of the area formula it is assumed that it should be written (1/2x)^2 it all makes sense now T_T
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EvGa
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Post subject: Re: could it be? OMG math Posted: Wed Apr 29, 2009 9:49 pm |
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evilpeta wrote: that is a common mistake, you're just squaring the X, and not the 1/2 before it.  ps: evga, typo on your first post.  AHHH, oh noes where!!? Oh, I didn't cube the x.. -.-
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evilpeta
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Post subject: Re: could it be? OMG math Posted: Wed Apr 29, 2009 9:49 pm |
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also try to rewrite 1/2x to x/2, since 1 over 2x is different from x over 2. it gets confusing sometimes 
_________________ wat
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EvGa
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Post subject: Re: could it be? OMG math Posted: Wed Apr 29, 2009 9:58 pm |
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Well poo.. I messed that up lol. I don't like combining the fraction with the x. Was trying to keep everything separated. Meant to have parenthesis around the fraction.. so walla, I threw in some more. Think it's fixed now. 
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evilpeta
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Post subject: Re: could it be? OMG math Posted: Wed Apr 29, 2009 10:03 pm |
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wasn't talking to you. lol  looking at the first picture the "1/2x" is rather confusing without parenthesis. any math teacher or judge will see that as 1 over 2x.
_________________ wat
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EvGa
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Post subject: Re: could it be? OMG math Posted: Wed Apr 29, 2009 10:11 pm |
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Joined: Apr 2008 Posts: 2612 Location: Texas
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Well I did the same thing in mine TAKS, so you live in Texas?
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ThatBluePerson
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Post subject: Re: could it be? OMG math Posted: Wed Apr 29, 2009 10:26 pm |
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EvGa wrote: Well I did the same thing in mine TAKS, so you live in Texas? lol yes.
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Brago
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Post subject: Re: could it be? OMG math Posted: Wed Apr 29, 2009 10:31 pm |
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Joined: Mar 2008 Posts: 1541 Location: The world has an ending, now you must find this ending.
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evilpeta
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Post subject: Re: could it be? OMG math Posted: Wed Apr 29, 2009 10:33 pm |
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dear God.
_________________ wat
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EvGa
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Post subject: Re: could it be? OMG math Posted: Wed Apr 29, 2009 10:50 pm |
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Joined: Apr 2008 Posts: 2612 Location: Texas
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ThatBluePerson wrote: EvGa wrote: Well I did the same thing in mine TAKS, so you live in Texas? lol yes. Ahh, I miss the good ole TAKS. I think they came out with it the last year I had to take mandatory state tests. We had TAAS before that. Good stuff. Brago wrote: Its c. Um, no.
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Midori
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Post subject: Re: could it be? OMG math Posted: Thu Apr 30, 2009 12:16 am |
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ThatBluePerson wrote: Yeah my algebrator says that the answer is 3PIx^3 which is what I got when I first worked out the problem.
damn TAKS creators.... no there was no E. You live in Texas? Where?
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boast
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Post subject: Re: could it be? OMG math Posted: Thu Apr 30, 2009 2:14 am |
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evilpeta wrote: wasn't talking to you. lol  looking at the first picture the "1/2x" is rather confusing without parenthesis. any math teacher or judge will see that as 1 over 2x. I thought the same as well. I was like, wtf, these choices aren't even CLOSE to the answer.
_________________ BlessedSoul - Battle Bard • Wartune - Warrior
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ThatBluePerson
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Post subject: Re: could it be? OMG math Posted: Thu Apr 30, 2009 2:51 am |
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X-Lax wrote: ThatBluePerson wrote: Yeah my algebrator says that the answer is 3PIx^3 which is what I got when I first worked out the problem.
damn TAKS creators.... no there was no E. You live in Texas? Where? Houston. 
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s0017
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Post subject: Re: could it be? OMG math Posted: Thu Apr 30, 2009 2:56 am |
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Heh, I took TAKS today as a Junior. I thought the sophomore test was 66 questions though, at least thats what my friend told me. O.o
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_Angels
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Post subject: Re: could it be? OMG math Posted: Thu Apr 30, 2009 11:18 am |
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ThatBluePerson wrote: _Angels wrote: evilpeta wrote: you sure the correct answer is within those options? lol idk if im right cuz this is old stuff but the volume of a cilinder is the area of the circunference times the height. area of circunference = pi*radius^2, and height = h. so: r = x/2, h = 6x V = pi*(radius)^2*height V = pi*(x/2)^2*6x V = pi*(x^2/4)*6x V = (3/2)*pi*x^3
so the answer is E) none of the above. or F) this test sucks balls. You are my new hero...but isn't 6*1/2=3? or i'm i a math noob? lol i have no idea ~_~ i dropped math a long time ago lol.__. whoever can do this kinda **** is my hero , D: im stuck at the first ;x
_________________ << banned on request. -cin >>
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NuclearSilo
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Post subject: Re: could it be? OMG math Posted: Thu Apr 30, 2009 11:43 am |
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pff, piece of cake. Just apply the formula
_________________ Playing Age of Wushu, dota IMBA
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+++
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Post subject: Re: could it be? OMG math Posted: Fri May 01, 2009 7:47 am |
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NuclearSilo wrote: pff, piece of cake. Just apply the formula Do you see a formula there?
_________________ C++ Coder
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