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 Post subject: could it be? OMG math
PostPosted: Wed Apr 29, 2009 9:04 pm 
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So today we had the state test that we have to take thanks to NCLB, for my sophomore class. It was Math. I practically finished all 62 questions in about an hour and a half. Except one question:

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If I replicated it correctly from memory. Anyways, I spent like the whole day trying to figure out the answer and I just couldn't. I know I will feel like a douche when you guys tell me right answer. But I just kept on trying and trying with everything I could think of and nothing. So now my perfect score streak since 1st grade is broken. :cry:

After some cursing out loud and getting escorted to the gym to finish there, I gave up and randomly selected B.


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 Post subject: Re: could it be? OMG math
PostPosted: Wed Apr 29, 2009 9:17 pm 
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was there an E. None of the above

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 Post subject: Re: could it be? OMG math
PostPosted: Wed Apr 29, 2009 9:17 pm 
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you sure the correct answer is within those options? lol
idk if im right cuz this is old stuff but the volume of a cilinder is the area of the circunference times the height. area of circunference = pi*radius^2, and height = h.
so:
r = x/2, h = 6x
V = pi*(radius)^2*height
V = pi*(x/2)^2*6x
V = pi*(x^2/4)*6x
V = (3/2)*pi*x^3

so the answer is E) none of the above. or F) this test sucks balls.

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Last edited by evilpeta on Wed Apr 29, 2009 9:21 pm, edited 2 times in total.

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 Post subject: Re: could it be? OMG math
PostPosted: Wed Apr 29, 2009 9:18 pm 
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I suck at this stuff but I know the answer isn't A or B.

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 Post subject: Re: could it be? OMG math
PostPosted: Wed Apr 29, 2009 9:24 pm 
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Yeah my algebrator says that the answer is 3PIx^3 which is what I got when I first worked out the problem.

damn TAKS creators.... no there was no E.


Last edited by ThatBluePerson on Wed Apr 29, 2009 9:25 pm, edited 1 time in total.

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 Post subject: Re: could it be? OMG math
PostPosted: Wed Apr 29, 2009 9:24 pm 
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evilpeta wrote:
you sure the correct answer is within those options? lol
idk if im right cuz this is old stuff but the volume of a cilinder is the area of the circunference times the height. area of circunference = pi*radius^2, and height = h.
so:
r = x/2, h = 6x
V = pi*(radius)^2*height
V = pi*(x/2)^2*6x
V = pi*(x^2/4)*6x
V = (3/2)*pi*x^3

so the answer is E) none of the above. or F) this test sucks balls.



You are my new hero...

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 Post subject: Re: could it be? OMG math
PostPosted: Wed Apr 29, 2009 9:25 pm 
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I thought it was 6/4x^3 also.

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 Post subject: Re: could it be? OMG math
PostPosted: Wed Apr 29, 2009 9:30 pm 
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_Angels wrote:
evilpeta wrote:
you sure the correct answer is within those options? lol
idk if im right cuz this is old stuff but the volume of a cilinder is the area of the circunference times the height. area of circunference = pi*radius^2, and height = h.
so:
r = x/2, h = 6x
V = pi*(radius)^2*height
V = pi*(x/2)^2*6x
V = pi*(x^2/4)*6x
V = (3/2)*pi*x^3

so the answer is E) none of the above. or F) this test sucks balls.



You are my new hero...


but isn't 6*1/2=3? or i'm i a math noob?


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 Post subject: Re: could it be? OMG math
PostPosted: Wed Apr 29, 2009 9:36 pm 
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you don't get to multiply 6 times 1/2 since the 1/2 turns into 1/4 due to radius squared.
lets take X out of the equation so it's easier to see.
radius = 1/2, height = 6
Volume = pi * (radius)^2 * height
V = pi * (1/2)^2 * 6
V = pi * 1/4 * 6
V = pi * 3/2

now you can just assume it's x^3 since its a volume, volume is measured in units ^3
meters^3, etc etc.

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 Post subject: Re: could it be? OMG math
PostPosted: Wed Apr 29, 2009 9:43 pm 
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Like evilpeta said, answer is: (3/2)pi(x^3).

pi*r^2*h
Pi*((1/2)x)^2)*(6x)
=Pi*(1/4)*(x^2)*(6x)
=Pi*(3/2)*(x^3)
=(3/2)*pi*(x^3)

Answer isn't there.

EDIT: Doh evil replied again.. easier to understand the way he put it.

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Last edited by EvGa on Wed Apr 29, 2009 9:56 pm, edited 3 times in total.

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 Post subject: Re: could it be? OMG math
PostPosted: Wed Apr 29, 2009 9:44 pm 
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still.. now that im thinking that 2/3 could of been a 3/2


Last edited by ThatBluePerson on Wed Apr 29, 2009 9:46 pm, edited 1 time in total.

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 Post subject: Re: could it be? OMG math
PostPosted: Wed Apr 29, 2009 9:45 pm 
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You're messing up at the very beginning. Radius = (1/2)x. You have to square the radius, thus you have to square 1/2 AND x. (1/2) squared = (1/4).

So ((1/2)x)^2 = (1/4)x^2

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 Post subject: Re: could it be? OMG math
PostPosted: Wed Apr 29, 2009 9:46 pm 
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that is a common mistake, you're just squaring the X, and not the 1/2 before it. :P
ps: evga, typo on your first post. :P

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 Post subject: Re: could it be? OMG math
PostPosted: Wed Apr 29, 2009 9:47 pm 
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evilpeta wrote:
that is a common mistake, you're just squaring the X, and not the 1/2 before it. :P


my teacher use to yell at us for that, i learned if (1/2x)^2 then we square both but if 1/2x^2 then the x is only square. but probably since the ^2 is part of the area formula it is assumed that it should be written (1/2x)^2

it all makes sense now T_T


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 Post subject: Re: could it be? OMG math
PostPosted: Wed Apr 29, 2009 9:49 pm 
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evilpeta wrote:
that is a common mistake, you're just squaring the X, and not the 1/2 before it. :P
ps: evga, typo on your first post. :P


AHHH, oh noes where!!?

Oh, I didn't cube the x.. -.-

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 Post subject: Re: could it be? OMG math
PostPosted: Wed Apr 29, 2009 9:49 pm 
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also try to rewrite 1/2x to x/2, since 1 over 2x is different from x over 2. it gets confusing sometimes :P

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 Post subject: Re: could it be? OMG math
PostPosted: Wed Apr 29, 2009 9:58 pm 
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Well poo.. I messed that up lol. I don't like combining the fraction with the x. Was trying to keep everything separated. Meant to have parenthesis around the fraction.. so walla, I threw in some more. Think it's fixed now. :P

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 Post subject: Re: could it be? OMG math
PostPosted: Wed Apr 29, 2009 10:03 pm 
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wasn't talking to you. lol
:oops:
looking at the first picture the "1/2x" is rather confusing without parenthesis. any math teacher or judge will see that as 1 over 2x.

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 Post subject: Re: could it be? OMG math
PostPosted: Wed Apr 29, 2009 10:11 pm 
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Well I did the same thing in mine :P

TAKS, so you live in Texas?

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 Post subject: Re: could it be? OMG math
PostPosted: Wed Apr 29, 2009 10:26 pm 
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EvGa wrote:
Well I did the same thing in mine :P

TAKS, so you live in Texas?


lol yes.


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 Post subject: Re: could it be? OMG math
PostPosted: Wed Apr 29, 2009 10:31 pm 
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Its c.

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 Post subject: Re: could it be? OMG math
PostPosted: Wed Apr 29, 2009 10:33 pm 
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dear God.

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 Post subject: Re: could it be? OMG math
PostPosted: Wed Apr 29, 2009 10:50 pm 
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ThatBluePerson wrote:
EvGa wrote:
Well I did the same thing in mine :P

TAKS, so you live in Texas?


lol yes.


Ahh, I miss the good ole TAKS. I think they came out with it the last year I had to take mandatory state tests. We had TAAS before that. Good stuff.

Brago wrote:
Its c.


Um, no.

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 Post subject: Re: could it be? OMG math
PostPosted: Thu Apr 30, 2009 12:16 am 
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ThatBluePerson wrote:
Yeah my algebrator says that the answer is 3PIx^3 which is what I got when I first worked out the problem.

damn TAKS creators.... no there was no E.


You live in Texas? Where?

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 Post subject: Re: could it be? OMG math
PostPosted: Thu Apr 30, 2009 2:14 am 
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evilpeta wrote:
wasn't talking to you. lol
:oops:
looking at the first picture the "1/2x" is rather confusing without parenthesis. any math teacher or judge will see that as 1 over 2x.



I thought the same as well. I was like, wtf, these choices aren't even CLOSE to the answer.

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 Post subject: Re: could it be? OMG math
PostPosted: Thu Apr 30, 2009 2:51 am 
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X-Lax wrote:
ThatBluePerson wrote:
Yeah my algebrator says that the answer is 3PIx^3 which is what I got when I first worked out the problem.

damn TAKS creators.... no there was no E.


You live in Texas? Where?


Houston. :P


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 Post subject: Re: could it be? OMG math
PostPosted: Thu Apr 30, 2009 2:56 am 
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Heh, I took TAKS today as a Junior. I thought the sophomore test was 66 questions though, at least thats what my friend told me. O.o


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 Post subject: Re: could it be? OMG math
PostPosted: Thu Apr 30, 2009 11:18 am 
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ThatBluePerson wrote:
_Angels wrote:
evilpeta wrote:
you sure the correct answer is within those options? lol
idk if im right cuz this is old stuff but the volume of a cilinder is the area of the circunference times the height. area of circunference = pi*radius^2, and height = h.
so:
r = x/2, h = 6x
V = pi*(radius)^2*height
V = pi*(x/2)^2*6x
V = pi*(x^2/4)*6x
V = (3/2)*pi*x^3

so the answer is E) none of the above. or F) this test sucks balls.



You are my new hero...


but isn't 6*1/2=3? or i'm i a math noob?


lol i have no idea ~_~ i dropped math a long time ago lol.__.
whoever can do this kinda **** is my hero , D:
im stuck at the first ;x

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 Post subject: Re: could it be? OMG math
PostPosted: Thu Apr 30, 2009 11:43 am 
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pff, piece of cake. Just apply the formula

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 Post subject: Re: could it be? OMG math
PostPosted: Fri May 01, 2009 7:47 am 
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NuclearSilo wrote:
pff, piece of cake. Just apply the formula

Do you see a formula there?

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